str_word_count

add a note User Contributed Notes

Aurelien Marchand
07-Oct-2006 12:06


I found a more reliable way to print, say the first 100 words and then print elipses. My code goes this way;



$threshold_length = 80; // 80 words max

$phrase = "...."; // populate this with the text you want to display

$abody = str_word_count($phrase,2);

if(count($abody) >= $threshold_length){ // gotta cut

  $tbody = array_keys($abody);

  echo "<p>" . substr($phrase,0,$tbody[$threshold_length]) . "... <span class=\"more\"><a href=\"?\">read more</a></span> </p>\n";

} else { // put the whole thing

  echo "<p>" . $phrase . "</p>\n";

}



For any questions, com.iname@artaxerxes2

lwright at psu dot edu
18-Aug-2006 02:51


If you are looking to count the frequency of words, try:



<?php



$wordfrequency = array_count_values( str_word_count( $string, 1) );



?>

rabin at rab dot in
05-Apr-2006 02:03


There is a small bug in the "trim_text" function by "webmaster at joshstmarie dot com" below. If the string's word count is lesser than or equal to $truncation, that function will cut off the last word in the string.





[EDITOR'S NOTE: above referenced note has been removed]





This fixes the problem:





<?php


function trim_text_fixed($string, $truncation = 250) {


    $matches = preg_split("/\s+/", $string, $truncation + 1);


    $sz = count($matches);


    if ( $sz > $truncation ) {


        unset($matches[$sz-1]);


        return implode(' ',$matches);


    }


    return $string;


}


?>

webmaster at joshstmarie dot com
26-Sep-2005 07:58


Trying to make an effiecient word splitter, and "paragraph limiter", eg, limit item text to 100, or 200 words and so-forth.



I don't know how well this compares, but it works nicely.



function trim_text($string, $word_count=100)

{

    $trimmed = "";

    $string = preg_replace("/\040+/"," ", trim($string));

    $stringc = explode(" ",$string);

    echo sizeof($stringc);

    if($word_count >= sizeof($stringc))

    {

        // nothing to do, our string is smaller than the limit.

      return $string;

    }

    elseif($word_count < sizeof($stringc))

    {

        // trim the string to the word count

        for($i=0;$i<$word_count;$i++)

        {

            $trimmed .= $stringc[$i]." ";

        }

        

        if(substr($trimmed, strlen(trim($trimmed))-1, 1) == '.')

          return trim($trimmed).'..';

        else

          return trim($trimmed).'...';

    }

}



$text = "some  test          text goes in here, I'm not sure, but ok.";

echo trim_text($text,5);

MadCoder
16-Aug-2005 12:12


Here's a function that will trim a $string down to a certian number of words, and add a...   on the end of it.

(explansion of muz1's 1st 100 words code)



----------------------------------------------

function trim_text($text, $count){

$text = str_replace("  ", " ", $text);

$string = explode(" ", $text);

for ( $wordCounter = 0; $wordCounter <= $count;wordCounter++ ){ 

$trimed .= $string[$wordCounter];

if ( $wordCounter < $count ){ $trimed .= " "; }

else { $trimed .= "..."; }

}

$trimed = trim($trimed);

return $trimed;

}



Usage

------------------------------------------------

$string = "one two three four";

echo trim_text($string, 3);



returns:

one two three...

jtey at uoguelph dot ca
15-Aug-2005 07:21


In the previous note, the example will only extract from the string, words separated by exactly one space.  To properly extract words from all strings, use regular expressions.



Example (extracting the first 4 words):

<?php

$string = "One    two three       four  five six";

echo implode(" ", array_slice(preg_split("/\s+/", $string), 0, 4));

?>



The above $string would not have otherwise worked when using the explode() method below.

jtey at uoguelph dot ca
14-Aug-2005 10:59


In reply to muz1's post below:



You can also take advantage of using other built in PHP functions to get to your final result.  Consider the following:

<?php

$string = "One two three four five six seven eight nine ten.";

// the first n words to extract

$n = 3;

// extract the words

$words = explode(" ", $string);

// chop the words array down to the first n elements

$firstN = array_slice($words, 0, $n);

// glue the 3 elements back into a spaced sentence

$firstNAsAString = implode(" ", $firstN);

// display it

echo $firstNAsAString;

?>



Or to do it all in one line:

<?php

echo implode(" ", array_slice(explode(" ", $string), 0, $n));

?>

muz1 at muzcore dot com
12-Aug-2005 03:56


This function is awesome however I needed to display the first 100 words of a string. I am submitting this as a possible solution but also to get feedback as to whether it is the most efficient way of doing it.



<?

                                    $currString = explode(" ", $string);

for ($wordCounter=0; $wordCounter<100; $wordCounter++) { echo $currString[$wordCounter]." "; }

?>

16-Jan-2005 10:38


This function seems to view numbers as whitespace. I.e. a word consisting of numbers only won't be counted.

aix at lux dot ee
14-Nov-2004 06:53


One function.

<?php

if (!function_exists('word_count')) {

function word_count($str,$n = "0"){

    $m=strlen($str)/2;

    $a=1;

    while ($a<$m) {

        $str=str_replace("  "," ",$str);

        $a++;

        }

    $b = explode(" ", $str);

    $i = 0; 

    foreach ($b as $v) {

        $i++;

        }

    if ($n==1) return $b;

    else  return $i;



    }

}

$str="Tere Tartu linn";

$c  = word_count($str,1); // it return an array

$d  = word_count($str); // it return int - how many words was in text

print_r($c);

echo $d;

?>

aidan at php dot net
26-Jun-2004 06:02


This functionality is now implemented in the PEAR package PHP_Compat.



More information about using this function without upgrading your version of PHP can be found on the below link:



http://pear.php.net/package/PHP_Compat

Kirils Solovjovs
23-Feb-2004 01:06


Nothing of this worked for me. I think countwords() is very encoding dependent. This is the code for win1257. For other layots you just need to redefine the ranges of letters...



<?php

function countwords($text){

        $ls=0;//was it a whitespace?

        $cc33=0;//counter

        for($i=0;$i<strlen($text);$i++){

                $spstat=false; //is it a number or a letter?

                $ot=ord($text[$i]);

                if( (($ot>=48) && ($ot<=57)) ||  (($ot>=97) && ($ot<=122)) || (($ot>=65) && ($ot<=90)) || ($ot==170) ||

                (($ot>=192) && ($ot<=214)) || (($ot>=216) && ($ot<=246)) || (($ot>=248) && ($ot<=254))  )$spstat=true;

                if(($ls==0)&&($spstat)){

                        $ls=1;

                        $cc33++;

                }

                if(!$spstat)$ls=0;

        }

        return $cc33;

}



?>

Artimis
15-Oct-2003 05:32


Never use this function to count/separate alphanumeric words, it will just split them up words to words, numbers to numbers.  You could refer to another function "preg_split" when splitting alphanumeric words.  It works with Chinese characters as well.

andrea at 3site dot it
19-May-2003 07:55


if string doesn't contain the space " ", the explode method doesn't do anything, so i've wrote this and it seems works better ... i don't know about time and resource





<?php


function str_incounter($match,$string) {


$count_match = 0;


for($i=0;$i<strlen($string);$i++) {


if(strtolower(substr($string,$i,strlen($match)))==strtolower($match)) {


$count_match++;


}


}


return $count_match;


}


?>





example 





<?php


$string = "something:something!!something";


$count_some = str_incounter("something",$string);


// will return 3


?>

megat at megat dot co dot uk
19-Apr-2003 09:29


[Ed: You'd probably want to use regular expressions if this was the case --alindeman @ php.net]





Consider what will happen in some of the above suggestions when a person puts more than one space between words. That's why it's not sufficient just to explode the string.

olivier at ultragreen dot net
11-Apr-2003 09:10


I will not discuss the accuracy of this function but one of the source codes above does this.





<?php


function wrdcnt($haystack) {


 $cnt = explode(" ", $haystack);


 return count($cnt) - 1;


}


?>





That could be replace by 





<?php


function wrdcnt($haystack) {


 return substr_count($haystack,' ') + 1;


}


?>





I doubt this does need to be a function :)

philip at cornado dot com
07-Apr-2003 10:30


Some ask not just split on ' ', well, it's because simply exploding on a ' ' isn't fully accurate.  Words can be separated by tabs, newlines, double spaces, etc.  This is why people tend to seperate on all whitespace with regular expressions.

rcATinterfacesDOTfr
16-Jan-2003 11:58


Here is another way to count words :

$word_count = count(preg_split('/\W+/', $text, -1, PREG_SPLIT_NO_EMPTY));

brettNOSPAM at olwm dot NO_SPAM dot com
10-Nov-2002 04:06


This example may not be pretty, but It proves accurate:





<?php


//count words


$words_to_count = strip_tags($body);


$pattern = "/[^(\w|\d|\'|\"|\.|\!|\?|;|,|\\|\/|\-\-|:|\&|@)]+/";


$words_to_count = preg_replace ($pattern, " ", $words_to_count);


$words_to_count = trim($words_to_count);


$total_words = count(explode(" ",$words_to_count));


?>





Hope I didn't miss any punctuation. ;-)

gorgonzola at nospam dot org
01-Nov-2002 06:48


i tried to write a wordcounter and ended up with this:





<?php


//strip html-codes or entities


$text = strip_tags(strtr($text, array_flip(get_html_translation_table(HTML_ENTITIES))));


//count the words


$wordcount = preg_match_all("#(\w+)#", $text, $match_dummy );


?>

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