number_format

add a note User Contributed Notes

giovanni dot cappellini at gmail dot com
26-Oct-2006 10:31


About the function of j-a-n at gmx dot de: it's useful, but the argument of the function is $number while the logic of the function requires it to be $in.

dwhitaker at dfwairport dot com
13-Sep-2006 10:56


You know sometimes we forget to add the basic cool stuff...



Found this over in the money_format section and felt some newbie is probably looking for it...



$val = "1000000";

echo number_format($val, 0, "", ","); // returns 1,000,000

26-Aug-2006 07:45


Unfortunately, this function is not multibyte-safe. If you want to use the typographically correct separator for thousands in Swiss German and UTF-8 ( - Unicode 2019), you'll only get the first byte - e.g. garbage -  since this function strips anything after the first byte, regardless of the charset used.

j-a-n at gmx dot de
11-Aug-2006 01:04


This function formats an decimal number to a String.

But it does'n use an fixed count of decimals but calculates the needed count of decimals.



<?

function formatNumber( $number, $decimals=2, $dec_point=".", $thousands_sep=",") {

    $nachkomma = abs($in - floor($in));

    $strnachkomma = number_format($nachkomma , $decimals, ".", "");



    for ($i = 1; $i <= $decimals; $i++) {

        if (substr($strnachkomma, ($i * -1), 1) != "0") {

            break;

        }

    }

    

    return number_format($in, ($decimals - $i +1), $dec_point, $thousands_sep);

}

?>

Example:



formatNumber( 100.00 );

--> 100

formatNumber( 100.50 );

--> 100.5

formatNumber( 100.1234 );

--> 100.12

formatNumber( 100.12, 4 );

--> 100.12

formatNumber( 100.12345, 4 );

--> 100.1234

04-Jun-2006 03:55


The modification to number_format below does what I actually want it to do, with currency, for example. I want it to show $1.40 and not $1.4 or $1.400 - except in the rare case where I have $1.435 for something, in which case I *don't* want it to round. The ugliness below serves my purpose.



function nof($number,$decimals) {

if (number_format($number,$decimals,'.',',') != $number) {

        return $number;

} else {

        return number_format($number,$decimals,'.',',');

        }

}

shpoffo .a.t.. g mail ...
01-Jun-2006 12:31


For those that need to print the word-form of a number ("twenty-three" instead of "23") I've found the following code to be useful.  This code is an improvement upon that posted in 2004 by armstrong @ rice.  Notably, the previous code did not properly compute large numbers (at least in PHP 4.x that I tested).  



The following code adds another variable to the function, which controls the display of fractional parts, and properly calculates values one thousand and above.



Zak

~ ~ ~ 



function num2words($num, $c=1) {

    $ZERO = 'zero';

    $MINUS = 'minus';

    $lowName = array(

         /* zero is shown as "" since it is never used in combined forms */

         /* 0 .. 19 */

         "", "one", "two", "three", "four", "five",

         "six", "seven", "eight", "nine", "ten",

         "eleven", "twelve", "thirteen", "fourteen", "fifteen",

         "sixteen", "seventeen", "eighteen", "nineteen");

    

    $tys = array(

         /* 0, 10, 20, 30 ... 90 */

         "", "", "twenty", "thirty", "forty", "fifty",

         "sixty", "seventy", "eighty", "ninety");

    

    $groupName = array(

         /* We only need up to a quintillion, since a long is about 9 * 10 ^ 18 */

         /* American: unit, hundred, thousand, million, billion, trillion, quadrillion, quintillion */

         "", "hundred", "thousand", "million", "billion",

         "trillion", "quadrillion", "quintillion");

    

    $divisor = array(

         /* How many of this group is needed to form one of the succeeding group. */

         /* American: unit, hundred, thousand, million, billion, trillion, quadrillion, quintillion */

         100, 10, 1000, 1000, 1000, 1000, 1000, 1000) ;

    

    $num = str_replace(",","",$num);

    $num = number_format($num,2,'.','');

    $cents = substr($num,strlen($num)-2,strlen($num)-1);

    $num = (int)$num;

    

    $s = "";

    

    if ( $num == 0 ) $s = $ZERO;

    $negative = ($num < 0 );

    if ( $negative ) $num = -$num;

    // Work least significant digit to most, right to left.

    // until high order part is all 0s.

    for ( $i=0; $num>0; $i++ ) {

       $remdr = (int)($num % $divisor[$i]);

       $num = $num / $divisor[$i];

       // check for 1100 .. 1999, 2100..2999, ... 5200..5999

       // but not 1000..1099,  2000..2099, ...

       // Special case written as fifty-nine hundred.

       // e.g. thousands digit is 1..5 and hundreds digit is 1..9

       // Only when no further higher order.

       if ( $i == 1 /* doing hundreds */ && 1 <= $num && $num <= 5 ){

           if ( $remdr > 0 ){

               $remdr = ($num * 10);

               $num = 0;

           } // end if

       } // end if

       if ( $remdr == 0 ){

           continue;

       }

       $t = "";

       if ( $remdr < 20 ){

           $t = $lowName[$remdr];

       }

       else if ( $remdr < 100 ){

           $units = (int)$remdr % 10;

           $tens = (int)$remdr / 10;

           $t = $tys [$tens];

           if ( $units != 0 ){

               $t .= "-" . $lowName[$units];

           }

       }else {

           $t = num2words($remdr, 0);

       }

       $s = $t." ".$groupName[$i]." ".$s;

       $num = (int)$num;

    } // end for

    $s = trim($s);

    if ( $negative ){

       $s = $MINUS . " " . $s;

    }

    

    if ($c == 1) $s .= " and $cents/100";

    

    return $s;

} // end num2words

ck at vowel dot se
26-May-2006 06:11


Again, the function for returning file size in human readable format, but with a tweek for displaying one decimal when size is less than 10 units.



<?php

function human_readable( $size )

{

   $count = 0;

   $format = array("B","KB","MB","GB","TB","PB","EB","ZB","YB");

   while(($size/1024)>1 && $count<8)

   {

       $size=$size/1024;

       $count++;

   }

   if( $size < 10 ) $decimals = 1;

   else $decimals = 0;

   $return = number_format($size,$decimals,'.',' ')." ".$format[$count];

   return $return;

}

?>



Thanks to "php dot net at alan-smith dot no-ip dot com" and "service at dual-creators dot de".

rudie at jouwmoeder dot nl
22-May-2006 05:30


number_format is pretty fast. It's much slower than calculation though:

<?php



$start = microtime(true);



echo "<pre>";

for ($i=0;$i<100000;$i++)

{

    echo number_format(microtime(true)-$start,25)."\n";

}

echo "<hr />Parsetime: ".(microtime(true)-$start);



?>

This takes 1.03 seconds all the time. Without the -$start in the number_format cmd, it takes exactly as long (I ran it about 20 times).

The simple calculation inside number_format takes relatively no time. Defining the number before entering it into number_format also gives no change:

{

    $num = microtime(true)-$start;

    echo number_format($num,25)."\n";

}



Which concludes it takes about .01 sec to do a thousand number_format.

If you'd do the same routine without the number_format, it'd take .75 seconds -> number_format very fast!

gfinale at hotmail dot com
15-May-2006 01:58


Thanks to armstrong ~~at~~ rice ~~dot~~ edu for your number to words function.  There does seem to be one glitch I've discovered, at least on my system.  Hundreds work but hundreds of thousands and hundreds of millions do not.  e.g. 100,000 or 100,000,000 hangs.

chris_cember at cinmach dot com
16-Mar-2006 05:40


// the mktime shortcut is a little trickier than it would first appear, even with a mod...



function text_number($n) {

    $mod = $n % (($n > 20)?10:20);

    return $n . (($mod==0)?"th":date("S",mktime(0,0,0,1,$mod,2000)));

}   



// or for those who don't appreciate shorthand:



function text_number($n) {

    if ($n > 20) {

        $mod_factor = 10;

    } else {

        $mod_factor = 20;

    }   

    $mod = $n % $mod_factor;

    if ($mod == 0) {

        $txt = "th";

    } else {

        $txt = date("S",mktime(0,0,0,1,$mod,2000));

    }   

    return $n . $txt;

}



/*

one issue comes up in numbers that mod to zero (which mktime will associate with the 31st of December, 1999).  another issue is between 23rd and 13rd, err I mean 13th.  If you use 20 (or even 30) all the time, however, you'll end up with 33th (or 43th).

*/

Steve Neill
04-Mar-2006 08:04


actually, you'd want to MOD the number to get it within a useful range first (1 .. 30).



Enjoy.

Steve Neill
04-Mar-2006 06:15


why go to all that trouble?



date('S', mktime(0,0,0,1,$str,2000));



works just as well!

mikesabatino at gmail dot com
01-Mar-2006 11:34


<?php

# Function to represent a number like '2nd', '10th', '101st' etc

function text_number($n)

{

    # Array holding the teen numbers. If the last 2 numbers of $n are in this array, then we'll add 'th' to the end of $n

    $teen_array = array(11, 12, 13, 14, 15, 16, 17, 18, 19);

    

    # Array holding all the single digit numbers. If the last number of $n, or if $n itself, is a key in this array, then we'll add that key's value to the end of $n

    $single_array = array(1 => 'st', 2 => 'nd', 3 => 'rd', 4 => 'th', 5 => 'th', 6 => 'th', 7 => 'th', 8 => 'th', 9 => 'th', 0 => 'th');

    

    # Store the last 2 digits of $n in order to check if it's a teen number.

    $if_teen = substr($n, -2, 2);

    

    # Store the last digit of $n in order to check if it's a teen number. If $n is a single digit, $single will simply equal $n.

    $single = substr($n, -1, 1);

    

    # If $if_teen is in array $teen_array, store $n with 'th' concantenated onto the end of it into $new_n

    if ( in_array($if_teen, $teen_array) )

    {

        $new_n = $n . 'th';

    }

    # $n is not a teen, so concant the appropriate value of it's $single_array key onto the end of $n and save it into $new_n

    elseif ( $single_array[$single] )

    {

        $new_n = $n . $single_array[$single];    

    }

    

    # Return new 

    return $new_n;

}

?>

MarcM
21-Feb-2006 02:03


For Zero fill - just use the sprintf() function



$pr_id = 1;

$pr_id = sprintf("%03d", $pr_id);

echo $pr_id;



//outputs 001

-----------------



$pr_id = 10;

$pr_id = sprintf("%03d", $pr_id);

echo $pr_id;



//outputs 010

-----------------



You can change %03d to %04d, etc.

adnan 'at' barakatdesigns 'dot' net
30-Jan-2006 11:43


Just a note to the author of the "zerofill" function, you may find it easier using the str_pad function



<?php

$num = 4;

$zerofill = 3;



echo str_pad($num, $zerofill, "0", STR_PAD_LEFT);



/* Returns the same wanted result of '004' */

?>

versae arroba gmail punto com
24-Jan-2006 07:17


A modification for kolnedra's function



<?



function humanReadable($val, $miles = 0){

    if($val>=1000)

        $val = humanReadable($val / 1024, ++$miles);

    else {

        $unidad = array('','K','M','G','T','P','E','Z','Y',

        'X','W','V','U','TD','S','R',

        'Q','PP','O','N','MI','L');

        $val = round($val, 2).$unidad[$miles].'B';

    }

    return $val;

}



?>

21-Jan-2006 04:48


A function to return a number with needed zeros at the beginning. Called "zerofill"



<?php

// $num = 4; $zerofill= 3; returns "004"

function zerofill ($num,$zerofill) {

    while (strlen($num)<$zerofill) {

        $num = "0".$num;

    }

    return $num;

}

?>

YumYum
11-Jan-2006 02:19


Jarrat's example below has a problem.  If the number is negative, the sign is dropped.  It always returns positive numbers.  The problem seems to be in the float cast in:



return (float) $number[0].'.'.$decimal;



I have not had a problem in PHP5 with:



return $number[0].'.'.$decimal;

Sprille
22-Dec-2005 12:45


as response to mike at phpeeb dot com.



You can do aritmetic even on strings, you just need a little function to sort it out like this :



function str2no($number){

  $number = str_replace(".", "", $number);

  $number = str_replace(",", ".", $number);

  return $number;

}



function no2str($number){

  $number = number_format($number,2, ',', '.');

  return $number;

}

  

echo no2str(str2no("1.200,50")*3);



// we use 1200.50 as input "1.200,50" is the danish string for this number

//this will output 3601.50 with right formatting = 3.601,50 as string

//nice to know when dealing with money.

kolnedra at gmail dot com
10-Oct-2005 09:28


A way to let a number (in this case an ammount of money) be shown in dutch annotation:

<?

// geld(123) >>> 123

// geld(123456) >>> 1.234.567

function geld($nm) {

    for ($done=strlen($nm); $done > 3;$done -= 3) { 

        $returnNum = ".".substr($nm,$done-3,3).$returnNum;

    }

    return substr($nm,0,$done).$returnNum;

}

?>

mikro_at_teppisti_dot_it
05-Oct-2005 07:04


This function formats numbers 'human readable' better (IMHO) than mircea way: 



function humanReadable($val,$thousands=0){

   if($val>=1000)

     $val=humanReadable($val/1024,++$thousands);

   else{

     $unit=array('','K','M','T','P','E','Z','Y');

     $val=round($val,2).$unit[$thousands].'B';

   }

   return $val;

 }

Jeroen de Bruijn [NL]
02-Oct-2005 06:02


If you want to display a number ending with ,- (like 200,-) when there are no decimal characters and display the decimals when there are decimal characters i use:



function DisplayDouble($value)

  {

  list($whole, $decimals) = split ('[.,]', $value, 2);

  if (intval($decimals) > 0)

    return number_format($value,2,".",",");

  else

    return number_format($value,0,".",",") .",-";

  }

aj at hotmail dot com
01-Oct-2005 12:18


In responce to astrolox;



This is because the numbers generated by performing math are double precision (which means pretty darn accurate) and not perfect precision (which would be what you get when you do the math on paper). For example 483.00 * 0.175 equals 84.525 on paper, but the computer can't do math with perfect precision and ends up with something like 84.52499999...



If dealing with money the best practice is to perform round() on your floating point numbers and always round up to the nearest cent, or add something small like .000001 before using number_format(). Personally I prefer to round().

astrolox at lawyersonline dot co dot uk
01-Aug-2005 11:34


Users should be aware of the following behaviour. 

I'm not sure if this is a PHP bug, libc bug, or if it's even a bug at all. So I thought I'd make a comment and allow everyone else to make up their own minds.



FreeBSD 4.3 PHP 4.3.3



<?php



// the comments show the output generated by this script



echo "input 8.525 output = ". number_format( 8.525, 2, '.', "") ."\n";

echo "input 8.525 output = ". number_format(8.525, 2, '.', "") ."\n";



// input 8.525 output = 8.53

// input 8.525 output = 8.53



$a = 483.00;

$b = 0.175;



$c = $a * $b;



echo "input \$c = $c type ". gettype($c) ." output = ". number_format( $c, 2, '.', "") ."\n";



// input $c = 84.525 type double output = 84.52



$d = 17.5;



$e = ( $a / 100 ) * $d;



echo "input \$e = $e type ". gettype($e) ." output = ". number_format( $e, 2, '.', "") ."\n";



// input $e = 84.525 type double output = 84.53



echo "input 63.745 output = ". number_format(63.745, 2, '.', "") ."\n";

echo "input 64.745 output = ". number_format(64.745, 2, '.', "") ."\n";

echo "input 65.745 output = ". number_format(65.745, 2, '.', "") ."\n";



// input 63.745 output = 63.74

// input 64.745 output = 64.75

// input 65.745 output = 65.75



?>

jarratt at si-works dot net
15-Jul-2005 06:06


With one of the payment providers they required a monitary input of 12345.67 always with a 2 decimal placing even if .00



if you have a number 12345.5 with only one decimal place i could find no sutable php function to guarentee two decimal palces and add a trailing zero if required, 



This fucntion should assist



function format_number($str,$decimal_places='2',$decimal_padding="0"){

        /* firstly format number and shorten any extra decimal places */

        /* Note this will round off the number pre-format $str if you dont want this fucntionality */

        $str           =  number_format($str,$decimal_places,'.','');     // will return 12345.67

        $number       = explode('.',$str);

        $number[1]     = (isset($number[1]))?$number[1]:''; // to fix the PHP Notice error if str does not contain a decimal placing.

        $decimal     = str_pad($number[1],$decimal_places,$decimal_padding);

        return (float) $number[0].'.'.$decimal;

}



/* examples */



format_number('1234');       // -->   1234.00

format_number('1234.5');     //-->   1234.50

format_number('1234.567');  //-->   1234.57

marc dot vanwoerkom at fernuni-hagen dot de
14-Jul-2005 09:53


See also the documentation for localeconv, which will provide values for decimal point and thousands separator from the C standard library.



Of course localeconv features many more locale information, like indicating to put the negative sign behind the value for some locale settings which can't be used to customize present number_format.

venimus777 at yahoo dot com
08-Jun-2005 08:25


You could use the following regular expression to divide

a number into parts:



$1-number without fractal part

$2-fractal part

$3-first 2 digits of the fractal part

$4-rest of the fractal part



the regex removes any leading and trailing symbols and leading zeros. It doesnt validate the number, so 12 41 is considered to be correct input!



english notation:

/^.*?[0]*([\d\s]+)(([\.][\d]{0,2})([\d]*))?.*?$/



french notation:

/^.*?[0]*([\d\s]+)(([\,][\d]{0,2})([\d]*))?.*?$/



<?php

// truncate the fractal part up to 2 digits of an "english number":

$number = '01,234.50789';

$trunc = preg_replace(

    '/^.*?[0]*([\d\,]+)(([\.][\d]{0,2})([\d]*))?.*?$/',

    '$1$3',

    $number

);

echo $trunc;

?>



Outputs:

1,234.50



$number='e00012 41.100001e-4fasfd';

would output:

12 41.10

woodynadobhar at hotmail dot com
18-May-2005 12:04


What do you do if some of your numbers have decimal places, and some don't?  You can switch between functions, but if you're building it in a loop, that's not a good solution.  Instead, we have the same as below, with a slight change:



function number_format_unlimited_precision($number,$decimal = '.'){

    $broken_number = explode($decimal,$number);

    if($broken_number[1]==0){

        return number_format($broken_number[0]);

    }else{

        return number_format($broken_number[0]).$decimal.$broken_number[1];

    };

};

stm555 at hotmail dot com
27-Apr-2005 11:54


I ran across an issue where I wanted to keep the entered precision of a real value, without arbitrarily rounding off what the user had submitted.



I figured it out with a quick explode on the number before formatting. I could then format either side of the decimal.



<?php

      function number_format_unlimited_precision($number,$decimal = '.')

      {

           $broken_number = explode($decimal,$number);

           return number_format($broken_number[0]).$decimal.$broken_number[1];

      }

?>

mike at phpeeb dot com
02-Apr-2005 05:13


Since number_format returns a string, you must perform all mathmatical functions on the number before applying number_format:



<?

$total = 100;

$total = number_format($total, 2);

$shipping = 20.00;

$grand_total = $total + $shipping;



echo number_format($grand_total, 2);



/* The above will return 21.00 because $total is now a string, and no longer an integer or float. Since a string will have a value of 1,  the addition of the two will return 21 and not 120. */



$total = 100;

$shipping = 20.00;

$grand_total = $total + $shipping;



echo number_format($grand_total, 2);



/* This works, and will return 120.00 as intended */



?>

php at mijav dot dk
31-Mar-2005 10:25


A bug was issued that -0,00 is invalid output from number_format(), but the bug was rejected since the number "-0.0000000000000000001E-999 is about -0". And the developer felt this was correct output.



Please beware of negative numbers close to zero, as they might produce this unusable (and in my opinion incorrect/off-description) output.

ChronoFish
24-Mar-2005 03:14


I was looking for an easy way to take a number (or string) and force into a specific format.  I came up with.  I apologize if this is redundant, but I could not find a simular function:



/***********************************

* string_format

***********************************/

function string_format($format, $string, $placeHolder = "#")

{            

    $numMatches = preg_match_all("/($placeHolder+)/", $format, $matches);              

    foreach ($matches[0] as $match)

    {

        $matchLen = strlen($match);

        $format = preg_replace("/$placeHolder+/", substr($string, 0, $matchLen), $format, 1);

        $string = substr($string, $matchLen);

    }

    return $format;

} 



To Use:



print string_format("(###)###-####", "4015551212");

will print out:

(401)555-1212



Hope this helps someone,



CF

tonywebman at NOSPAM dot telusplanet dot net
24-Feb-2005 05:14


While trying to add variables whose values had been processed with number_format() I found an interesting gotcha. Perhaps this might help others.



Since number_format() returns a string, numbers returned that DO NOT have a comma in them will still be added but numbers that DO have a comma will not be added because PHP considers them a string and ignores them.



e.g. #1

$quant_mag = 1;

$cost_mag = 100;

$quant_ffr = 1

$cost_ffr = 100;



$ext_mag = number_format($quant_mag * $cost_mag,2);

$ext_ffr = number_format($quant_ffr * $cost_ffr,2);



$total_cost = $ext_mag + $ext_ffr;



// $total cost is: 200



e.g. #2

$quant_mag = 10;

$cost_mag = 100;

$quant_ffr = 1

$cost_ffr = 100;



$ext_mag = number_format($quant_mag * $cost_mag,2);

$ext_ffr = number_format($quant_ffr * $cost_ffr,2);



$total_cost = $ext_mag + $ext_ffr;

// $total cost is: 100 (not 1100 as you would expect) because $ext_mag is ignored because php interprets its value (1,000) as a string so it won't add it to $ext_ffr.

keyg at auralplanet dot com
23-Nov-2004 10:56


if you want &nbsp; as a separator and use windows charset this piece of code may help:



<?php

$number=number_format($number,2,'.',chr(0xA0));

?>

brandonprudent at yahoo dot com
11-Oct-2004 02:52


To convert numbers to thier textual representations, you can use an adapted version of the Number::Spell Perl module. The PHP conversion can be found here: http://pear.php.net/package/Numbers_Words

GeekPrices Dot Com
07-Oct-2004 08:57


this also works as well



$number = "29346.99"; //value

echo "$" .number_format($number, 2, '.', ',');



produces $29,346.99

Svein Tjonndal (sveint at yahoo dot com)
15-Sep-2004 10:18


If you use space as a separator, it will break on that space in HTML tables...



Furthermore, number_format doesn't like '&nbsp;' as a fourth parameter. I wrote the following function to display the numbers in an HTML table.



  function numberfix($number)

  {

    $number = number_format($number,0,","," ");

    return str_replace(" ", "&nbsp;", $number);

  }



For use in:

<table><tr><td><?php echo $number; ?></td></tr></table>

drew at zitnay dot com
18-Aug-2004 02:17


A more reliable and concise way of doing what S. Rahmel was trying to do below is as follows:



<?php

$field_inhalt = str_replace(array(".", ","), array("", "."), $field_inhalt);

?>



The str_replace() call will first replace all dots with blanks, and then replace all commas with dots.  That way, it doesn't break down when you try a number over one million (i.e. 1.010.453,21).



Drew

mircea at vtds dot co dot uk
03-Jun-2004 12:57


This function formats numbers 'human readable':





function byte_format($input, $dec=0)


{ 


  $prefix_arr = array(" B", "K", "M", "G", "T");


  $value = round($input, $dec);


  $i=0;


  while ($value>1024)


  { 


     $value /= 1024;


     $i++;


  }


  $return_str = round($value, $dec).$prefix_arr[$i];


  return $return_str;


}

S. Rahmel
12-Mar-2004 06:47


if you converted a number to a German format with number_format() and want to save it in mySQL, you first have to change the number format back to an English format.



For example 

10.453,21 >>>> 10453.21



Here is an example how to do this:



    $field_array=explode(".", $field_inhalt);

    $field_inhalt=$field_array[0].$field_array[1];

    $foeld_array=explode(",", $field_inhalt);

    $field_inhalt=$field_array[0].".".$feld_array[1];

    $field_inhalt=sprintf($field_inhalt, 2);



$field_inhalt is the variable of the actual number you want to change to the english format.

chandu at chandu dot org
08-Mar-2004 09:29


People here in India are more used to counting money in Lakhs & Crores .. so here is the code for formatting the commas with thousands for the first time and then with hundred multiples from there after.



Ex: 1234567  ->  12,34,567



<?php



function makecomma($input)

{

    // This function is written by some anonymous person - I got it from Google

    if(strlen($input)<=2)

    { return $input; }

    $length=substr($input,0,strlen($input)-2);

    $formatted_input = makecomma($length).",".substr($input,-2);

    return $formatted_input;

}



function formatInIndianStyle($num){

    // This is my function

    $pos = strpos((string)$num, ".");

    if ($pos === false) { $decimalpart="00";}

    else { $decimalpart= substr($num, $pos+1, 2); $num = substr($num,0,$pos); }



    if(strlen($num)>3 & strlen($num) <= 12){

                $last3digits = substr($num, -3 );

                $numexceptlastdigits = substr($num, 0, -3 );

                $formatted = makecomma($numexceptlastdigits);

                $stringtoreturn = $formatted.",".$last3digits.".".$decimalpart ;

    }elseif(strlen($num)<=3){

                $stringtoreturn = $num.".".$decimalpart ;

    }elseif(strlen($num)>12){

                $stringtoreturn = number_format($num, 2);

    }



    if(substr($stringtoreturn,0,2)=="-,"){$stringtoreturn = "-".substr($stringtoreturn,2 );}



    return $stringtoreturn;

}



$num = 1234567;

echo  formatInIndianStyle($num);



?>

armstrong ~~at~~ rice ~~dot~~ edu
23-Feb-2004 08:33


I submitted this question earlier, but I found the answer myself.  To convert a number to its word form (e.g. 34 to "thirty four")  try the function below.  It turned out to be a lot more complex than I thought!



I'm using it for printing dollar ammounts, so the cents get printed like 13/100



I converted most of it from this java code http://mindprod.com/inwords.html so credit goes to him for doing the hard part.



<?

/**

* convert long integer into American English words.

* e.g. -12345 -> "minus twelve thousand forty-five"

* Handles negative and positive integers

* on range -Long.MAX_VALUE .. Long.MAX_VALUE;

* It cannot handle Long.MIN_VALUE;

*/



function num2words( $num ){

    $ZERO = "zero";

    $MINUS = "minus";

    $lowName = array(

          /* zero is shown as "" since it is never used in combined forms */

          /* 0 .. 19 */

          "", "one", "two", "three", "four", "five",

          "six", "seven", "eight", "nine", "ten",

          "eleven", "twelve", "thirteen", "fourteen", "fifteen",

          "sixteen", "seventeen", "eighteen", "nineteen");



    $tys = array(

          /* 0, 10, 20, 30 ... 90 */

          "", "", "twenty", "thirty", "forty", "fifty",

          "sixty", "seventy", "eighty", "ninety");



    $groupName = array(

          /* We only need up to a quintillion, since a long is about 9 * 10 ^ 18 */

          /* American: unit, hundred, thousand, million, billion, trillion, quadrillion, quintillion */

          "", "hundred", "thousand", "million", "billion",

          "trillion", "quadrillion", "quintillion");



    $divisor = array(

          /* How many of this group is needed to form one of the succeeding group. */

          /* American: unit, hundred, thousand, million, billion, trillion, quadrillion, quintillion */

          100, 10, 1000, 1000, 1000, 1000, 1000, 1000) ;



    $num = str_replace(",","",$num);

    $num = number_format($num,2,'.','');

    $cents = substr($num,strlen($num)-2,strlen($num)-1);

    $num = (int)$num;



    $s = "";



    if ( $num == 0 ) $s = $ZERO;

    $negative = ($num < 0 );

    if ( $negative ) $num = -$num;



    // Work least significant digit to most, right to left.

    // until high order part is all 0s.

    for ( $i=0; $num>0; $i++ ) {

        $remdr = (int)($num % $divisor[$i]);

        $num = $num / $divisor[$i];

        // check for 1100 .. 1999, 2100..2999, ... 5200..5999

        // but not 1000..1099,  2000..2099, ...

        // Special case written as fifty-nine hundred.

        // e.g. thousands digit is 1..5 and hundreds digit is 1..9

        // Only when no further higher order.

        if ( $i == 1 /* doing hundreds */ && 1 <= $num && $num <= 5 ){

            if ( $remdr > 0 ){

                $remdr += $num * 10;

                $num = 0;

            } // end if

        } // end if

        if ( $remdr == 0 ){

            continue;

        }

        $t = "";

        if ( $remdr < 20 ){

            $t = $lowName[$remdr];

        }

        else if ( $remdr < 100 ){

            $units = (int)$remdr % 10;

            $tens = (int)$remdr / 10;

            $t = $tys [$tens];

            if ( $units != 0 ){

               $t .= "-" . $lowName[$units];

            }

        }else {

            $t = $inWords($remdr);

        }

        $s = $t . " " . $groupName[$i] . " "  . $s;

        $num = (int)$num;

    } // end for

    $s = trim($s);

    if ( $negative ){

        $s = $MINUS . " " . $s;

    }



    $s .= " and $cents/100";



    return $s;

} // end inWords



?>

cruzf_AT_fibertel.com.ar
08-Nov-2003 03:03


You could add padding zeros like this:



<?

$number="129";

$number=sprintf("%08d",$number);

?>

j dot bos at bytewriters dot nl
02-Jun-2003 03:45


If I'm not mistaking all these examples of adding leading zeros will not really work with floats. Sometimes though one needs it to have it working with floats as well.



With the function below use 2, 3 or 5 parameters. Don't ask me why 4 don't work, the number_format() function seems to have problems with that. At least my version of PHP has that "feature".



function leading_zero( $aNumber, $intPart, $floatPart=NULL, $dec_point=NULL, $thousands_sep=NULL) {        //Note: The $thousands_sep has no real function because it will be "disturbed" by plain leading zeros -> the main goal of the function

  $formattedNumber = $aNumber;

  if (!is_null($floatPart)) {    //without 3rd parameters the "float part" of the float shouldn't be touched

    $formattedNumber = number_format($formattedNumber, $floatPart, $dec_point, $thousands_sep);

    }

  //if ($intPart > floor(log10($formattedNumber)))

    $formattedNumber = str_repeat("0",($intPart + -1 - floor(log10($formattedNumber)))).$formattedNumber;

  return $formattedNumber;

  }



echo leading_zero(21.12345678, 4, 5);    // Output: 0021.12346

echo leading_zero(21.12345678, 4);    // Output: 0021.12345678

echo leading_zero(21.12345678, 3, 0); // Output: 021

echo leading_zero(21.12345678, 3, 5, ",", ""); // Output: 021,12346



addition: Just like the number_format I haven't found a way *not* to round a number while changing the decimal point and the thousands seperator.

sgj at dr dot com
18-May-2003 09:04


Just an observation:

The number_format rounds the value of the variable.



$val1 = 1.233;

$val2 = 1.235;

$val3 = 1.237;



echo number_format($val1,2,",","."); // returns: 1,23

echo number_format($val2,2,",","."); // returns: 1,24

echo number_format($val3,2,",","."); // returns: 1,24

Theo Diem
25-Mar-2003 05:45


formatting numbers may be more easy if u use number_format function.



I also wrote this :

function something($number)

{

    $locale = localeconv();

    return number_format($number,

       $locale['frac_digits'],

        $locale['decimal_point'],

        $locale['thousands_sep']);

}



hope this helps =)

[]'s

andrew at crucible dot co dot nz
05-Jan-2002 08:56


Remember that number_format returns a string, so you shouldn't run a number_format on a variable that's already a product of number_format (it will only take the first token of the string)...





eg. echo number_format("123,456.00", 2);


produces: 123.00

sctemplarknight at hotmail dot com
12-Dec-2001 05:27


number_format($number,$precision,".","") should be used when setting the value of form elements because if you read the number into a double upon submission, it will only store digits before the comma.


<p>


ie. <input type="text" value="<?php echo(number_format(2.5343,2,".","")">

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