JDDayOfWeek

(PHP 3, PHP 4, PHP 5)

JDDayOfWeek -- Returns the day of the week

Description

mixed jddayofweek ( int julianday [, int mode] )

Returns the day of the week. Can return a string or an integer depending on the mode.

表格 1. Calendar week modes

ModeMeaning
0 (Default) Returns the day number as an int (0=Sunday, 1=Monday, etc)
1 Returns string containing the day of week (English-Gregorian)
2 Returns a string containing the abbreviated day of week (English-Gregorian)


add a note add a note User Contributed Notes
nrkkalyan at rediffmail dot com
26-Feb-2005 02:08
You can get todays day time and date using this code

echo date("d")." ";
echo date("m")." ";
echo date("Y")." ";
echo date("h:i:s A");

ECHO ' <br/>';
echo jddayofweek ( cal_to_jd(CAL_GREGORIAN, date("m"),date("d"), date("Y")) , 1 );
rizwan at drexel dot edu
17-Jan-2005 01:52
Maybe it is me since I am a newb but the above post on the use of mktime is wrong.  You need to use GregorianToJD instead.  I noticed this because when I used mktime, my day labels went backwards as I went forward through the month.
php at xtramicro dot com
07-Sep-2004 11:28
Be aware that date() and mktime() only work as long as you move within the UNIX era (1970 - 2038 / 0x0 - 0x7FFFFFFF in seconds). Outside that era those functions are only generating errors.

In other words: mktime(0, 0, 0, 12, 31, 1969) *DOES NOT* work (and so doesn't date() fed with with mktime()'s result from above). But cal_to_jd(CAL_GREGORIAN, 12, 11, 1969) *DOES WORK*.

And please note that the calendar-extension's functions arguments follow the US date order: month - day - year.