imagecolorresolve

(PHP 3 >= 3.0.2, PHP 4, PHP 5)

imagecolorresolve -- 取得指定颜色的索引值或有可能得到的最接近的替代值

说明

int imagecolorresolve ( resource image, int red, int green, int blue )

本函数可以保证对所请求的颜色返回一个颜色索引,要么是确切值要么是所能得到最接近的替代值。

如果从文件创建了图像,只有图像中使用了的颜色会被辨析。仅出现在调色板中的颜色不会被辨析。

参见 imagecolorclosest()


add a note add a note User Contributed Notes
ceo at l-i-e dot com
03-Jan-2002 07:55
Okay, so sometimes it's really IMPORTANT to get the exact color you want, only it's not *IN* the Image, and ImageColorResolve just isn't "close enough".

The following code is a disgustingly gross hack, rather slow, but it does that.

$colorcount = array();
for ($x = 0; $x < $width; $x++){
   for ($y = 0; $y < $height; $y++){
       $colorindex = imagecolorat($jpg, $x, $y);
       if (!isset($colorcount[$colorindex])){
           $colorcount[$colorindex] = 1;
       }
       else{
           $colorcount[$colorindex]++;
       }
   }
}
asort($colorcount);
reset($colorcount);

$black = imagecolorexact($jpg, 0, 0, 0);
if ($black == -1){
   $goner = key($colorcount);
   $rgb = imagecolorsforindex($jpg, $goner);
   #error_log("Need black: About to kill $goner ($rgb[red], $rgb[green], $rgb[blue]) which was only used in $colorcount[$goner] pixels", 0);
   unset($colorcount[$goner]);
   imagecolordeallocate($jpg, $goner);
   $black = imagecolorallocate($jpg, 0, 0, 0);
}
if ($black == -1){
   $black = imagecolorresolve($jpg, 0, 0, 0);
   #error_log("Damn!  STILL couldn't allocate the color!", 0);
}