ftp_fput

说明

bool ftp_fput ( resource ftp_stream, string remote_file, resource handle, int mode [, int startpos] )

ftp_fput() 函数用来上传一个在已经打开的文件中的数据到 FTP 服务器，参数 handle 为所打开文件的句柄。参数 remote_file 为上传到服务器上的文件名。传输模式参数 mode 只能为 (文本模式) FTP_ASCII 或 (二进制模式) FTP_BINARY 其中的一个。

例子 1. ftp_fput() example
<?php // open some file for reading $file = 'somefile.txt'; $fp = fopen($file, 'r'); // connect to the server $conn_id = ftp_connect($ftp_server); $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); // try to upload the file if(ftp_fput($conn_id, $file, $fp, FTP_ASCII)) { echo "Successfully uploaded $file\n"; } else { echo "There was a problem while uploading $file\n"; } // close the connection and the file handler ftp_close($conn_id); fclose($fp); ?>

注: 参数 startpos 只适用于 4.3.0 以上版本。

如果成功则返回 TRUE，失败则返回 FALSE。

参见 ftp_put()，ftp_nb_fput() 和 ftp_nb_put()。

add a note User Contributed Notes

info at daniel-marschall dot de
20-Apr-2006 03:04


This is a function i wrote to copy a complete directory to a FTP-Server-folder.



function ftp_uploaddirectory($conn_id, $local_dir, $remote_dir)

{

  @ftp_mkdir($conn_id, $remote_dir);

  $handle = opendir($local_dir);

  while (($file = readdir($handle)) !== false)

  {

    if (($file != '.') && ($file != '..'))

    {

      if (is_dir($local_dir.$file))

      {

        ftp_uploaddirectory($conn_id, $local_dir.$file.'/', $remote_dir.$file.'/');

      }

      else

        $f[] = $file;

    }

  }

  closedir($handle);

  if (count($f))

  {

    sort($f);

    @ftp_chdir($conn_id, $remote_dir);

    foreach ($f as $files)

    {

      $from = @fopen("$local_dir$files", 'r');

      @ftp_fput($conn_id, $files, $from, FTP_BINARY);

    }

  }

}



Example:



$conn_id = @ftp_connect($server);

@ftp_login ($conn_id, $username, $passwort);

ftp_uploaddirectory($conn_id, 'mydirectory/', 'theftpdirectory/');

@ftp_quit($conn_id);



I hope you'll find it useful.

BobFrank <rsfranc at yahoo dot com dot br>
24-Aug-2003 12:10


FTP upload server 2 server

<?php

$FTP_HOST ="ftp.br.geocities.com"; 

$FTP_USER ="bobfrank";

$FTP_PW   ="mypasswd";

$FTP_ROOT_DIR="/";

$LOCAL_SERVER_DIR  = "images/";

$FTP_DIR = "mydir/";

$handle=opendir($LOCAL_SERVER_DIR);

while (($file = readdir($handle))!==false)

{

    if(!is_dir($file)){

        $f[]="$file";        

      }

}

closedir($handle);

sort($f);

$count=0;

$mode = FTP_BINARY; // or FTP_ASCII

$conn_id = ftp_connect($FTP_HOST); 

if(ftp_login($conn_id, $FTP_USER, $FTP_PW)){

    print "from: ".$LOCAL_SERVER_DIR."<br>";

    print "to: ".$FTP_HOST.$FTP_ROOT_DIR.$FTP_DIR."<br>";

    ftp_pwd($conn_id);

    ftp_mkdir($conn_id,$FTP_DIR);

    ftp_chdir($conn_id,$FTP_DIR); 

    foreach($f as $files) {

        $from = fopen($LOCAL_SERVER_DIR.$files,"r");     

        if(ftp_fput($conn_id, $files, $from, $mode)){

            $count +=1;

            print $files."<br>";

        }

    }

    ftp_quit($conn_id);

}

print "upload : $count files.";

?>

darian lassan at yahoo de
05-Feb-2003 02:00


If you want to pass a string containing the filename as source and not a resource handle use ftp_put() instead. Trivial but not mentioned here.

add a note